In terms of basic units of mass (M), length (L), time (T) and charge (Q), the dimensions of magnetic permeability of vacuum ((μ0)) would be
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a
[MLQ-2]
b
[LT-1Q-1]
c
[ML2T-1Q-2]
d
[LTQ-1]
answer is A.
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Detailed Solution
The force per unit length experienced due to two wires in which current is flowing in the same direction is given by dFdl=μ04π2I1I2d⇒MLT−2[L]=μ0A2[L]⇒ MLT−2[L]=μ0Q2T2L⇒μ0=MLQ−2