The Thallium-201 half-life is 74 hours. If the sample has an activity of 80 millicuries initially, what will be the activity after 9.25 days?

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2.5 mCi

5 mCi

10 mCi

20 mCi

answer is C.

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Detailed Solution

9.25 days is equal to three half-lives for Tl-201. The fraction remaining is then:1/2×1/2×1/2=1/8 . Thus 1/8 of 80 mCi i.e. 10mCi remains.

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