Thee plates A, B, C each of area 50 cm2 have separation 3 mm between A and B and 3 mm between B and C fig. The energy stored when the plates are fully charged is

The given combination is equivalent to two capacitors connected in parallel. So, the total capacitance =2ε0A/d∴Energy stored =122ε0AdV2=ε0AV′dSubstituting the given values, we get Energy stored =1.6 μJ