First slide

Cell

Question

There are N cells in the circuit of fig. The e.m.f' and internal resistance of each cell is E and r
respectively. The points A and I in the circuit divide the circuit into n and (N -n) cells. The current in the circuit is

Easy

A

E / r
B

n E /r
C

NE /nr
D

zero

Solution

The current is given by

$\begin{array}{l} i = \frac{V}{R} = \frac{nE + (N - n) E}{nr + (N - n) r} \\ = \frac{NE}{Nr} = \frac{E}{r} \end{array}$

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