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Q.

There are n1 photons of frequency  v1 in a beam of light. In an equally energetic beam, there are n2 photons of frequency v2. Then the correct relation is

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a

n1n2=1

b

n1n2=v1v2

c

n1n2=v2v1

d

n1n2=v12v22

answer is C.

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Detailed Solution

E=nhv⇒v∝1n⇒n1n2=v2v1.
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