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Q.

There are two equally charged identical metal spheres A and B repel each other with a force 3×10-5 N. Another identical uncharged sphere C is touched with A and then placed at the mid-point between A and B. Net force on C is

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a

1×10−5N

b

2×10−5N

c

1.5×10−5N

d

3×10−5N

answer is D.

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Detailed Solution

If same charges on spheres A and Bare q, then force,             F=14πε0q2r2=3×10−5NCharge on A and C after touching,              qA′=qC=q2Net force on C,F=FA+FB∴  F=14πε0(q/2)(q/2)(r/2)2−14πε0(q/2)×q(r/2)2=14πε0rq2r2−214πε0q2r2=−14πε0⋅qr2=3×10−5N
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