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Q.

There are two identical capacitors, the first one is uncharged and filled with a dielectric constant K while the other one is charged to potential V having air between its plates. If two capacitors are joined end to end, the common potential will be

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a

VK−1

b

KVV+1

c

KVV−1

d

VK+1

answer is D.

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V=q1+q2C1+C2=0+C0VC0+C0K=VK+1
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