Questions
There are two identical small holes of area of cross-section a on the opposite sides of a tank containing a liquid of density . The difference in height between the holes is h. Tank is resting on a smooth horizontal surface. Horizontal force which will has to be applied on the tank to keep it in equilibrium is
detailed solution
Correct option is C
Net force (reaction) = F=FB−FA=dpBdt−dpAdt =avBρ×vB−avAρ×vA∴ F=aρvB2−vA2 …(i)According to Bernoulli's theorem pA+12ρvA2+ρgh=pB+12ρvB2+0⇒12ρvB2−vA2=ρgh⇒vB2−vA2=2ghFrom equation (i), F=2aρgh.Talk to our academic expert!
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A large open tank has two holes in the wall. One is a square hole of side L at a depth y from the top and the other is a circular hole of radius R at a depth 4y from the top. When the tank is completely filled with water the quantities of water flowing out per second from both the holes are the same. Then R is equal to
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