There are two radioactive substance A & B, Decay constant of B is two times that of A. initially, both have equal number of nuclei. After n half lives of A, rate of disintegration of both are equal. The value of ‘h’ is
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a
4
b
2
c
1
d
5
answer is C.
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Detailed Solution
Let λA=λ ∴ λB=2λ.If is total number of nuclei in A & B at t = 0, times initial rate of distntegration of A=λNo,and initial rate of disintegration of B=2λNoAs λB=2λA⇒TB=TA2After one half life of A−dNdtA=λNo2Equivalently, after two half lives of B−dNdtB=2λNo4=λNo2∴−dNdtA=−dNdtBn=1,i.e After one half life of A