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There are two radioactive substances A and B. Decay constant of B is two times that of A. Initially, both have equal number of nuclei. After n half lives of A, rate of disintegration of both are equal. The value of n is
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Correct option is C
λB=2λA nTA=N02n=NATB=12TA N022n=NB λANA=λBNB λAN02n=2λAN022nGive 22n2n=2 22n−n=21 n=1Talk to our academic expert!
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