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Q.

There are two radioactive substances A and B. Decay constant of B is two times that of A. Initially, both have equal number of nuclei. After n half lives of A, rate of disintegration of both are equal. The value of n is

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a

4

b

2

c

1

d

5

answer is C.

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Detailed Solution

λB=2λA        nTA=N02n=NATB=12TA       N022n=NB     λANA=λBNB     λAN02n=2λAN022nGive    22n2n=2       22n−n=21     n=1
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