There are two spherical balls A and B of the same material with same surface, but the diameter of A is half that of B. If A and B are heated to the same temperature and then allowed to cool, then
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
rate of cooling is same in both
b
rate of cooling of A is four times that of B
c
rate of cooling of A is twice that of B
d
rate of cooling of A is 14 times that of B
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Rate of cooling, RC=AεσT4−T04mc=AεσT4−T04VρC⇒ RC∝AV∝1r∝1( Diameter ) (∵ m=ρV)Since diameter of A is half that of B, its rate of cooling will be twice that of B.