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# There are two spherical balls A and B of the same material with same surface, but the diameter of A is half that of B. If A and B are heated to the same temperature and then allowed to cool, then

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a
rate of cooling is same in both
b
rate of cooling of A is four times that of B
c
rate of cooling of A is twice that of B
d
rate of cooling of A is 14 times that of B
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detailed solution

Correct option is C

Rate of cooling, RC=AεσT4−T04mc=AεσT4−T04VρC⇒ RC∝AV∝1r∝1( Diameter ) (∵ m=ρV)Since diameter of A is half that of B, its rate of cooling will be twice that of B.

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