Projection Under uniform Acceleration

Question

There are two values of time for which a projectile is at the same height. The sum of these two times is equal to (T = time of flight of the projectile)

Easy

Solution

${t}_{OA}={\mathrm{t}}_{\mathrm{BC}}\phantom{\rule{0ex}{0ex}}{\text{To tind t}}_{OA}\text{}+{t}_{OB}\phantom{\rule{0ex}{0ex}}$

${\mathrm{t}}_{\mathrm{OA}}+{\mathrm{t}}_{\mathrm{OB}}={t}_{BC}+{t}_{OB}=\mathrm{T}$

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