First slide

Stress and strain

Question

There are two wires of same material and same length while the diameter of second wire is 2 times the diameter of first wire, then ratio of extension produced in the wires
by applying same load will be

Moderate

A

1 : 1
B

2 : 1
C

1 : 2
D

4 : 1

Solution

$l = \frac{FL}{AY} ∴ l \propto \frac{1}{r^{2}} (F, L and Y are constant)$
$\frac{l_{1}}{l_{2}} = {(\frac{r_{2}}{r_{1}})}^{2} = (2)^{2} = 4$

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