First slide

Drift velocity

Question

There is a current of 1.344 amp in a copper wire whose area of cross-section normal to the length of the wire is 1mm². If the number of free electrons per cm³ is 8.4x 10²² then the drift velocity would be

Moderate

A

1 .0 mm per sec
B

1.0 metre per sec
C

0 .1mm per sec
D

0.01mm per sec

Solution

$\begin{array}{l} v_{d} = \frac{i}{nAe} \\ = \frac{1 .344}{(8 \cdot 4 \times 10^{22} \times 10^{6}) (1 \times 10^{- 6}) \times (1 .6 \times 10^{- 19})} m / s \\ = 1 \times 10^{- 4} m / s = 0 \cdot 1 mm / \sec \end{array}$

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