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There is a current of 1.344 amp in a copper wire whose area of cross-section normal to the length of the wire is 1mm2. If the number of free electrons per cm3 is 8.4x 1022 then the drift velocity would be

a
1 .0 mm per sec
b
1.0 metre per sec
c
0 .1mm per sec
d
0.01mm per sec

detailed solution

Correct option is C

vd=inAe=1.3448⋅4×1022×1061×10−6×1.6×10−19m/s=1×10−4m/s=0⋅1mm/sec

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