First slide

Drift velocity

Question

There is a current of 1.344 A in a copper wire whose area of cross-section normal to the length of the wire is 1 mm². If the number of free electrons per cm³ is $8.4 \times 10^{22}$ , then the drift velocity would be

Easy

A

1.0 mm/s
B

1.0 m/s
C

0.1 mm/s
D

0.01 mm/s

Solution

$\begin{array}{l} ν_{d} = \frac{i}{n A e} = \frac{1.344}{10^{- 6} \times 1.6 \times 10^{- 19} \times 8.4 \times 10^{22}} \\ = \frac{1.344}{10 \times 1.6 \times 8.4} = 0.01 c m / s = 0.1 m m / s \end{array}$

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