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Q.

There is a current of 1.344 A in a copper wire whose area of cross-section normal to the length of the wire is 1 mm2. If the number of free electrons per cm3 is 8.4 ×  1022,  then the drift velocity would be

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a

1.0 mm/s

b

1.0 m/s

c

0.1 mm/s

d

0.01 mm/s

answer is C.

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Detailed Solution

νd = inAe =  1.34410−6 × 1.6 ×10−19× 8.4 ×1022  =1.34410 × 1.6 × 8.4 = 0.01  cm/s=0.1  mm/s
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