There is an electric field E in x-direction. If the work done on moving a charge 0.2C through a distance of 2m along a line making an angle 60o with the X-axis is 4.0 J , what is the value of E

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3 N/C

4 N/C

5N/C

20 NC−1

answer is D.

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Detailed Solution

W= qV = q Edcosθ ⇒4=0.2×E×2 cos 60 =0.2 E×2×0.5 ∴E=40.2=20 NC−1

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