There exists a uniform electric field E in horizontal direction. A particle having mass m and charge q is projected with a velocity u in upward direction in uniform gravitational field g as shown in the figure. The radius of curvature of path of particle at the highest point is

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q2E2u2m2g2

q2E2u2m2g3

q2E2u2mg

None of these

answer is B.

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Detailed Solution

After time t the particle will reach the highest point of its trajectory where its horizontal component of velocity VVh=qEmug Therefore radius of curvature ρ is given by Vh2/ρ = g ⇒ρ=q2E2u2m2g3

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