Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

There exists a uniform electric field E in horizontal direction. A particle having mass m and charge q is projected with a velocity u in upward direction in uniform gravitational field g as shown in the figure. The radius of curvature of path of particle at the highest point is

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya

a

q2E2u2m2g2

b

q2E2u2m2g3

c

q2E2u2mg

d

None of these

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

After time t the particle will reach the highest point of its trajectory where its horizontal component of velocity  VVh=qEmug  Therefore radius of curvature  ρ is given by Vh2/ρ  = g                                                                               ⇒ρ=q2E2u2m2g3
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

best study material, now at your finger tips!

  • promsvg

    live classes

  • promsvg

    progress tracking

  • promsvg

    24x7 mentored guidance

  • promsvg

    study plan analysis

download the app

gplay
mentor

Download the App

gplay
whats app icon
personalised 1:1 online tutoring