Q.

There exists a uniform electric field E in horizontal direction. A particle having mass m and charge q is projected with a velocity u in upward direction in uniform gravitational field g as shown in the figure. The radius of curvature of path of particle at the highest point is

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a

q2E2u2m2g2

b

q2E2u2m2g3

c

q2E2u2mg

d

None of these

answer is B.

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Detailed Solution

After time t the particle will reach the highest point of its trajectory where its horizontal component of velocity  VVh=qEmug  Therefore radius of curvature  ρ is given by Vh2/ρ  = g                                                                               ⇒ρ=q2E2u2m2g3
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There exists a uniform electric field E in horizontal direction. A particle having mass m and charge q is projected with a velocity u in upward direction in uniform gravitational field g as shown in the figure. The radius of curvature of path of particle at the highest point is