There exists a uniform electric field E in horizontal direction. A particle having mass m and charge q is projected with a velocity u in upward direction in uniform gravitational field g as shown in the figure. The radius of curvature of path of particle at the highest point is

Question

Infinity Learn · Accepted Answer

After time t the particle will reach the highest point of its trajectory where its horizontal component of velocity  $$VVh=qEmug$$  Therefore radius of curvature  ρ is given by $$Vh2/$$ρ  $$=$$ g                                                                               ⇒ρ$$=q2E2u2m2g3$$

There exists a uniform electric field E in horizontal direction. A particle having mass m and charge q is projected with a velocity u in upward direction in uniform gravitational field g as shown in the figure. The radius of curvature of path of particle at the highest point is

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material