There is a tall building with cylindrical base standing in a horizontal smooth plane. Radius of the cylinder base of the building is R = 8 m. Two friends Ram and Shyam standing at points P and Q respectively, on opposite side of the building. Ram standing at P (at a distance 10 m from the centre of the cylindrical base of the building) knows that his friend Shyam is standing at Q behind the building. The line joining P and Q passes through the centre of the base of the building. Distance between P and Q is 50 m. Ram wants to throw a ball to Shyam but he realises that the building is too tall and he cannot throw the ball over it. Ram throws the ball at a speed of 20 m/s such that his friend Shyam at Q has to move minimum distance to catch it. What is the minimum distance (in meter) that Shyam standing at Q will have to move to catch the ball?
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answer is 40.
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Detailed Solution
In the figure, we can observe the top view of the situation. Ram will throw the ball so that it passes tangentially (just missing) to the building. The ball can fall on line Pt at different locations for different angles of projection.Shyam standing at Q will have to move a minimum distance if the ball lands at N such that QN⊥Pt. In similar, triangles, △POM and ΔPQNlmin50=R10⇒lmin=810×50∴lmin=40m