There is a uniform electric field of strength 103 V /m along y-axis. A body of mass 1 gm and charge 10-6 C is projected into the field from origin along the positive x-axis with a velocity 10 m/s. Its speed in m/s after 10 s is (Neglect gravitation)

Body moves along the parabolic path.For vertical motion: By using v = u + at, we havevy=0+QEm.t=10−6×10310−3×10=10m/sFor horizontal motion: Its horizontal velocity remains the same, i.e., after 10 s, horizontal velocity of body vx = 10 m/s.Velocity after 10 s, v = vx2+vy2 = 10✓2 m/s