Questions
In a thermodynamic process, pressure of a fixed mass of a gas is changed in such a manner that the gas molecules gives out 20 J of heat and 10 J of work is done on the gas. If the initial internal energy of the gas was 40 J, then the final internal energy will be
detailed solution
Correct option is C
ΔQ=ΔU+ΔW=Uf−Ui+ΔW⇒30=Uf−40+10⇒Uf=60JTalk to our academic expert!
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