In a thermodynamic process, a system absorbs 2 kilo calorie of heat and at the same time does 500 J of work. What is the change in internal energy of the system :
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a
–500 J
b
500 J
c
7900 J
d
8900 J
answer is C.
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Detailed Solution
Since dQ=dU+dW∴ dU=dQ−dW.Here dQ=2000 cal. =2000×4.2=8400J and dW=500 J∴ dU=8400−500=7900JThus, correct choice is (3).