Questions
In a thermodynamic process, a system absorbs 2 kilo calorie of heat and at the same time does 500 J of work. What is the change in internal energy of the system :
detailed solution
Correct option is C
Since dQ=dU+dW∴ dU=dQ−dW.Here dQ=2000 cal. =2000×4.2=8400J and dW=500 J∴ dU=8400−500=7900JThus, correct choice is (3).Talk to our academic expert!
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