First slide

Heat ;work and internal energy

Question

A thermodynamic system goes from states (i) P₁, V to 2P₁, V (ii) P, V₁ to P, 2V₁. Then work done in the two cases is

Easy

A

Zero, Zero
B

Zero, PV₁
C

PV₁, Zero
D

PV₁, P₁V₁

Solution

$(i) Case \to Volume = constant \Rightarrow \int P d V = 0$
$(ii) Case \to P = constant \Rightarrow \int_{V_{1}}^{2 V_{1}} P d V = P \int_{V_{1}}^{2 V_{1}} d V = P V_{1}$

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