First slide

Graphs

Question

A thermodynamic system undergoes cyclic process ABCDA as shown in Fig.The work done by the system in the cycle is:

Difficult

A

$P_{0} V_{0}$
B

$2 P_{0} V_{0}$
C

$\frac{P_{0} V_{0}}{2}$
D

zero

Solution

Work done by the system in the cycle
= Area under P-V curve and V-axis
$= \frac{1}{2} (2 P_{0} - P_{0}) (2 V_{0} - V_{0}) + [- (\frac{1}{2}) (3 P_{0} - 2 P_{0}) (2 V_{0} - V_{0})] = \frac{P_{0} V_{0}}{2} - \frac{P_{0} V_{0}}{2} = 0$

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