Q.

A thermodynamic system undergoes cyclic process ABCDA as shown in figure. The work done by the system in the cycle is

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a

P0V0

b

2P0V0

c

P0V02

d

Zero

answer is 4.

(Detailed Solution Below)

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Detailed Solution

In a cyclic process work done is equal to the area under the cycle and is positive if the cycle is clockwise and negative if anticlockwise. As is clear from figure, WAEDA=+ area of ∆AED=+12P0V0 WBCEB=-Area of ∆BCD=-12P0V0The network done by the system isWnet =WAEDA+WBCEB=+12P0V0-12P0V0= zero
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