First slide

Work done by gas

Question

A thermodynamic system undergoes cyclic process ABCDA as shown in figure. The work done by the system in the cycle is

Easy

A

$P_{0} V_{0}$
B

$2 P_{0} V_{0}$
C

$\frac{P_{0} V_{0}}{2}$
D

Zero

Solution

In a cyclic process work done is equal to the area under the cycle and is positive if the cycle is clockwise and negative if anticlockwise.
$A s i s c l e a r f r o m f i g u r e, W_{A E D A} = + a r e a o f ∆ A E D = + \frac{1}{2} P_{0} V_{0} W_{B C E B} = - A r e a o f ∆ B C D = - \frac{1}{2} P_{0} V_{0}$
The network done by the system is
$W_{net} = W_{A E D A} + W_{B C E B}$
$= + \frac{1}{2} P_{0} V_{0} - \frac{1}{2} P_{0} V_{0} = zero$

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