Download the app

Questions  

 

A thermodynamical process is shown in fig. With PA=3×104Pa;VA=2×103m3 ;

PB=8×104N/m2;VD=5×103m3, In the processes AB and BC, 600J and 200J of heat is added to the system respectively . The change in internal energy of the system in process AC would be 

 

a
560J
b
800 J
c
600 J
d
640 J

detailed solution

Correct option is A

W=WA→B+WB→C=O+P(V2−V1)=8×104(5×10−3−2×10−3)=240JΔQ=ΔU+ΔW600+200=ΔU+240560J=ΔU

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

A cyclic process ABCA is shown in the V-T diagram process on the P – V diagram is


phone icon
whats app icon