First slide

Conduction

Question

The thickness of a metallic plate is 0.4 cm. The temperature between its two surfaces is 20⁰C. The quantity of heat flowing per second is 50 cal from 5 cm² area. The coefficient of thermal conductivity (in CGS system) will be

Moderate

A

0.2
B

0.3
C

0.4
D

0.5

Solution

We know that,
$\frac{Q}{t} = \frac{K A (Δ θ)}{l}$
$50 = \frac{5 \times 20 K}{0.4}$
or $K = \frac{50 \times 0.4}{5 \times 20} = 0.2$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App