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Q.

The thickness of a metallic plate is 0.4 cm. The temperature between its two surfaces is 200C. The quantity of heat flowing per second is 50 cal from 5 cm2 area. The coefficient of thermal conductivity (in CGS system) will be

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a

0.2

b

0.3

c

0.4

d

0.5

answer is A.

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Detailed Solution

We know that, Qt=KA(Δθ)l50=5×20K0.4or    K=50×0.45×20=0.2
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