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The thickness of a metallic plate is 0.4 cm. The temperature between its two surfaces is 200C. The quantity of heat flowing per second is 50 cal from 5 cm2 area. The coefficient of thermal conductivity (in CGS system) will be
detailed solution
Correct option is A
We know that, Qt=KA(Δθ)l50=5×20K0.4or K=50×0.45×20=0.2Talk to our academic expert!
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A body of length 1 m having cross sectional area has heat flow through it at the rate of 6000 Joule/sec. Then find the temperature difference if K = 200 J
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