First slide

Magnetic flux and induced emf

Question

A thin circular ring of area A is perpendicular to uniform magnetic field of induction B. A small cut is made in the ring and a galvanometer is connected across the ends
such that the total resistance of circuit is R. When the ring is suddenly squeezed to zero area, the charge flowing through the galvanometer is

Moderate

A

$\frac{B R}{A}$
B

$\frac{A B}{R}$
C

$A B R$
D

$B^{2} A / R^{2}$

Solution

$Q = \frac{Δ ϕ}{R} = \frac{ϕ_{2} - ϕ_{1}}{R} = \frac{B A - 0}{R} = \frac{B A}{R}$

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