First slide
Law of conservation of angular momentum
Question

A thin circular ring of mass M and radius r is rotating about an axis passing through its centre and perpendicular to its plane with a constant angular velocity ω. Two objects, each of mass m are attached gently to the opposite ends of a diameter of the ring'

The ring now rotates with angular velocity ω

Moderate
Solution

We know that the angular momentum is conserved,.i.e.,
I1ω=I2ω or M.R2ω=(M+2m)R2ω ω=(M+2m)

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