A thin circular ring of mass M and radius r is rotating about an axis passing through its centre and perpendicular to its plane with a constant angular velocity ω. Two objects, each of mass m are attached gently to the opposite ends of a diameter of the ring'The ring now rotates with angular velocity ω
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a
ω(M−2m)M+2m
b
ωM(M−m)
c
ω(M+2m)M
d
ωM(M+2m)
answer is D.
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Detailed Solution
We know that the angular momentum is conserved,.i.e.,I1ω=I2ω′ or M.R2ω=(M+2m)R2ω′∴ ω′=Mω(M+2m)
A thin circular ring of mass M and radius r is rotating about an axis passing through its centre and perpendicular to its plane with a constant angular velocity ω. Two objects, each of mass m are attached gently to the opposite ends of a diameter of the ring'The ring now rotates with angular velocity ω