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A thin circular ring of mass M and radius r is rotating about its axis with an angular speed ω . Two particles having mass m each are now attached at diametrically opposite points. The angular speed of the ring will become.

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a

ωMM+m

b

ωMM+2m

c

ωM−2mM+2m

d

ωM+2mM

answer is B.

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Detailed Solution

Angular Momentum Conservation Li=Lf ⇒Mr2ω=Mr2ω'+2mr2ω' ⇒ω'=ωMM+2m

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A thin circular ring of mass M and radius r is rotating about its axis with an angular speed ω . Two particles having mass m each are now attached at diametrically opposite points. The angular speed of the ring will become.