A thin circular wire carrying a current I has a magnetic moment M. The shape of the wire is changed to a square and it carries the same current. It will have a magnetic moment

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4π2M

4πM

π4M

answer is D.

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Detailed Solution

Iπr2=M 2πr=lM=Iπl24π2=Il24π r=12πWhen it is made a square l = 4a.M1=Ia2=Il216 a=14MM1 =Il2/4πIl2/16=164π=4πM1=πM4

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