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Questions  

A thin circular wire carrying a current I has a magnetic moment M. The shape of the wire is changed to a square and it carries the same current. It will have a magnetic moment 

a
M
b
4π2M
c
4πM
d
π4M

detailed solution

Correct option is D

Iπr2=M                       2πr=lM=Iπl24π2=Il24π                         r=12πWhen it is made a square l = 4a.M1=Ia2=Il216                       a=14MM1 =Il2/4πIl2/16=164π=4πM1=πM4

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