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Q.

A  thin conducting  rod  of  rectangular cross section and of length  'ℓ'=25  meter  and  mass ‘m’  =  4  kg  lies  on  the  horizontal  table.  It can translate along x-axis. Coefficient of friction between the  rod  and  the  table  is  'μ'=12. If the current in the conductor is 2 ampere, then  the minimum magnitude of uniform constant magnetic field strength (in Tesla) that should exist in space such that conducting rod just starts to translate along x-axis is P .Value of P=  ------- (take g  = 10  m/sec2)

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answer is 2.

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Detailed Solution

Let say magnetic field acts such that magnetic force F makes an angle θ with horizontal.Vertical :​ N=mg-FsinθHorizontal :​ fL=Fcosθ⇒μN=Fcosθ⇒μ(mg-Fsinθ)=Fcosθ⇒F=μmgμsinθ+cosθFor F to be minimum, (μsinθ+cosθ) should be maximum∴ddθ(μsinθ+cosθ)=0⇒μcosθ−sinθ=0⇒μ=sinθcosθ⇒sinθ=μ1+μ2 and cosθ=11+μ2 ∴Fmin=μmg1+μ2⇒iℓBmin=μmg1+μ2⇒Bmin=μmgiℓ1+μ2=(0.5)(40)(45)(52)=2T
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