A thin copper rod AB of length l is rotating with constant angular velocity about an axis passing through the end A and perpendicular to the plane of page in a uniform magnetic field of induction $\vec{B}$ as shown in the figure. P and Q are two points on the rod such that $A P = \frac{l}{4}$ and $A Q = \frac{l}{2} .$ If ‘V’ is the induced potential at a point on the rod, then $(V_{Q} - V_{P}) / (V_{B} - V_{A}) i s$

Question

Infinity Learn · Accepted Answer

$$(4)VP$$−$$VA=12$$ Bω  $$l42$$,   VQ−$$VA=12$$ Bω  $$l22and$$   VB−$$VA=12$$ Bω$$l2$$∴   VQ−VPVB−VA  $$=$$  $$l22$$ − $$l42l2$$  $$=14$$−$$116=316$$.

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