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A thin copper rod AB of length 1m is rotating with constant angular velocity ω = 5 rad/s. A magnetic field of induction B = 0.5 T with its direction perpendicular to the rod exists in that region as shown in the figure. Then induced potential difference between mid point C and end B of the rod is

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a

0.9375 V

b

1.25 V

c

0.7528 V

d

1.5 V

answer is A.

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Detailed Solution

VC = Speed of C = 5 x 12m/s=52m/sVB = Speed of B = 5 x 1 m/s=5 m/sPoint B is at higher potential.∴Potential difference between B and C =B x Length BC x VB+VC2=0.5 x 0.5×5+2.52volt=0.9375 volt

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