Questions
A thin copper rod PQ of length 1 m is made to move with velocity V = 2 m/s in a uniform magnetic field of induction B = 1.5 Tesla as shown in the figure. Then induced potential difference between points P and R is
detailed solution
Correct option is A
(1)VP−VQ=BlV sin θ = 1.5 × 0.25 ×2×sin300=0.375 volt.Talk to our academic expert!
Similar Questions
A bar magnet of magnetic moment is placed in a uniform magnetic induction field of . If each pole of the magnet experiences a force of . The length of the magnet is
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