First slide

Motional EMF

Question

A thin copper rod PQ of length 1 m is made to move with velocity V = 2 m/s in a uniform magnetic field of induction B = 1.5 Tesla as shown in the figure. Then induced potential difference between points P and R is

Moderate

A

0.375 volt
B

02.5 volt
C

5.3 volt
D

$2 \sqrt{3}$ volt

Solution

(1)
$\begin{array}{l} V_{P} - V_{Q} = B l V \sin θ = 1.5 \times 0.25 \times 2 \times \sin 30^{0} \\ = 0.375 v o l t . \end{array}$

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