A thin copper wire of length L increases in length by 1% when heated from 0°C to 100°C . If a thin copper plate of area 2L2 is heated from 0oC to 50°C , the percentage increase in its area will be

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answer is A.

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Detailed Solution

ΔAA×100%=2×ΔLL×100%ΔLL=α⋅Δθ22×12%=1%

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