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Q.

A thin equiconvex lens is made of glass of refractive index 1.5 and its focal length is 0.2 m, if it acts as a concave lens of 0.5 m focal length when dipped in a liquid, the refractive index of the liquid is

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a

178

b

158

c

138

d

98

answer is B.

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Detailed Solution

flfa=aμg−1lμg−1⇒−0.50.2=1.5−1lμg−1⇒lμg−1=−0.2 ⇒lμg=0.8=45⇒ aμg aμl=45⇒1.5 aμl=45 ⇒aμl=158
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