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Q.

A thin glass (refractive index 1.5) lens has optical power of –8D in air.  Its optical power in a liquid medium with refractive index 1.6 will be

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a

25D

b

–25D

c

1D

d

–1D

answer is C.

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Detailed Solution

P=1f=(μ−1)(1R1+1R2) P1P2=(aμg−1)(ℓμg−1)⇒8P2=0.5(1.51.6−1) ∴P2=1D
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