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Q.

A thin insulate wire forms a plane spiral of N = 100 turns carrying a current I = 2.3 A. The inner and outer radii are equal to a = 5 cm and b = 10cm. Find the magnetic field (In 10-3 T) at the centre of spiral [In 2 = 0.69] is

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a

1

b

2

c

3

d

4

answer is B.

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Detailed Solution

Consider an elementary part of radius x and width dx.B=∫dB=∫R1R2 μ0I2x100R2−R1dx2.3×2π×10−7×1005×10−2ln⁡2=2.003×10−4T
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