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Q.

A thin lens focal length f1 and its aperture has diameter d. It forms an image of intensity I. Now the central part of the aperture upto diameter d2 is blocked by an opaque paper. The focal length and image intensity will change to

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a

f2 and I2

b

f and I4

c

3f4 and I2

d

f and 3I4

answer is D.

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Detailed Solution

I∝A2⇒I2I1=A2A12=πr2−πr24πr2=34 ⇒I2=34I1 and focal length remains unchanged
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