Q.
A thin lens made of glass of refractive index 1.5 has a front surface + 11 D power and back surface – 6 D. If this lens is submerged in a liquid of refractive index 1.6, the resulting power of the lens is
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a
– 0.5 D
b
+ 0.5 D
c
– 0.625 D
d
+ 0.625 D
answer is C.
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Detailed Solution
Total power P=P1+P2=11−6=5D Also flfa= aμg−1μg−1⇒PaPl= aμg−1μg−1 ⇒5Pl=(1.5−1)(1.5/1.6−1)⇒Pl=−0.625D
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