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Q.

A thin lens made of glass of refractive index 1.5 has a front surface + 11 D power and back surface – 6 D. If this lens is submerged in a liquid of refractive index 1.6, the resulting power of the lens is

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a

– 0.5 D

b

+ 0.5 D

c

– 0.625 D

d

+ 0.625 D

answer is C.

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Detailed Solution

Total power P=P1+P2=11−6=5D  Also flfa= aμg−1μg−1⇒PaPl= aμg−1μg−1 ⇒5Pl=(1.5−1)(1.5/1.6−1)⇒Pl=−0.625D
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