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Q.

A thin magnetic needle oscillates in the horizontal plane with a time period of 2.0 s. If the needle is broken into 4 equal parts perpendicular to its length, then the time period of each part will be

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a

0.5 s

b

1.0 s

c

1.5 s

d

2.0 s

answer is A.

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Detailed Solution

T=2πIMBFor each part M becomes one-fourth while l becomes (1/64)th. Hence, T'=2πI/64M/4B=T4=24=0.5 s
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