First slide

Capacitance

Question

A thin metal plate P is inserted between the plates of a parallel plate capacitor of capacity C in such a way that its edges touch the two plates. The capacity now becomes :

Easy

A

C/2
B

2C
C

zero
D

$\infty$

Solution

Capacity C = $\frac{∆ Q}{∆ V}, Here, ∆ V = 0 so C = \infty$

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