First slide

Rolling motion

Question

A thin ring and a disc have same mass and roll without slipping with the same linear velocity v. If the total kinetic energy of the loop is 8 J, the kinetic energy of the disc must be

Moderate

A

8 J
B

16 J
C

6 J
D

4 J

Solution

During rolling total KE of loop = ${mv}^{2} = 8 J$
Total KE of disc = $\frac{3}{4} {mv}^{2} = \frac{3}{4} 8 = 6 J$

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