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Q.

A thin ring and a solid disc are rolling without slipping on horizontal surface with same kinetic energy. The objects have the same mass and radius. If ω1 and ω2 be the angular velocities of the ring and the disc respectively, then ω1ω2 is equal to

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a

23

b

12

c

32

d

32

answer is C.

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Detailed Solution

12m(ω1R)2+12(mR2)ω12=12m(ω2R)2+12(12mR2)ω22⇒ω12+ω12=ω22+12ω22⇒ ω12ω22=34⇒ω1ω2=32

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