A thin rod AB of length l is bent at right angles at point P such that length AP = l3. The rod is freely suspended from point P and the segment PB of the rod makes an angle θ with vertical. Then θ is equal to
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a
tan-112
b
tan-114
c
tan-123
d
tan-134
answer is B.
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Detailed Solution
PC1=l6 and PC2=l3Taking moment of mg3 and 2mg3 about the point P, mg3x PC1sin(90o-θ)=2mg3PC2sinθ⇒tanθ=12.PC1PC2=12l/6l/3=14⇒θ=tan-114