First slide

Angular momentum

Question

A thin rod AB of mass 1 Kg and length 2m can rotate about a spindle passing through its mid point C and perpendicular to its length. Now a 2 N-m torque is applied to the rod for 10 seconds. Then angular momentum of the rod at the end of 10 S is

Moderate

A

20 N-m-s
B

10 N-m-s
C

5 N-m-s
D

40 N-m-s

Solution

$\frac{dL}{dt} = τ, \int_{0}^{L} dL = τ \int_{0}^{t} dt \Rightarrow L = τt = 2 \times 10 N - m - s = 20 N - m - s$

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