A thin rod AB of mass m and Length ‘l' is lying on a frictionless horizontal surface. Two forces, each of magnitude F are applied to the rod at points A and M. Then select the correct option.

Net force on the rod = F - F = 0. So acceleration of centre of mass is zero and the rod is transnational equilibrium.Resultant torque about the centre of mass C=F .  l2  +  F . l4=3Fl4.Moment of inertia of the rod about an axis perpendicular to the rod passing through the centre of mass  IC=112  ml2∴   Angular acceleration α = τIC = 3Fl4  ×   12ml2  =  9Fml