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Simple hormonic motion

Question

A thin rod AB of mass m and length l is hinged at end A and suspended freely. A particle of mass m is attached at the lower end B. The lower end of the rod is slightly pulled to one side and released. Then frequency of oscillation of the rod is

Difficult
Solution

rc = Distance of C.O.M. of (rod + particle) system from  A=m×l2+  m  ×  lm+m=3l4

IA=13ml2+ml2=43ml2         T=2πIAm.g rc=2π43ml2m.g(3l/4)  =  2π16l9g=8π3lg           f=1T=38π  gl



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