Gravitaional potential at a point

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Question

A thin rod of length L is bent to form a semicircle. The mass of rod is M. What will be the gravitational potential at the centre of the circle?

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Solution

$\begin{array}{l} F o r s e m i c i r c l e, π R = L \\ r a d i u s, R = \frac{L}{π} \\ p o t e n t i a l V = - \frac{G M}{R} = - \frac{π G M}{L} \end{array}$

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