Questions
A thin semicircular conducting ring (PQR) of radius 'r' is falling with its plane vertical in a horizontal magnetic field B, as shown in figure. The potential difference developed across the ring when its speed is v, is :
detailed solution
Correct option is D
Induced emf = Bv(2r) = 2rBvTalk to our academic expert!
Similar Questions
A conductor rod AB moves parallel to X-axis in a uniform magnetic field, pointing in the positive X-direction. The end A of the rod gets
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